- Name: python-pycurl
- Version: 7.15.5.1
- Release: 8.el5
- Epoch:
- Group: Development/Languages
- License: LGPL
- Url: http://pycurl.sourceforge.net/
- Summary: A Python interface to libcurl
- Architecture: ppc
- Size: 0
- Distribution: Red Hat
- Vendor: Red Hat, Inc.
- Packager: Red Hat, Inc. <http://bugzilla.redhat.com/bugzilla>
Description:
PycURL is a Python interface to libcurl. PycURL can be used to fetch
objects identified by a URL from a Python program, similar to the
urllib Python module. PycURL is mature, very fast, and supports a lot
of features.
- BuildArch:
- ExcludeArch:
- ExclusiveArch:
- Cookie: js20-bc2-12.build.redhat.com 1285780733
- Buildhost: js20-bc2-12.build.redhat.com
Generated packages:
- python-pycurl-7.15.5.1-8.el5.i386
- python-pycurl-7.15.5.1-8.el5.i386
- python-pycurl-7.15.5.1-8.el5.x86_64
- python-pycurl-7.15.5.1-8.el5.x86_64
Other version of this rpm:
